C++98stlbeginner
std::search_n
C++98 · The Foundation · Compiler flag: -std=c++98
Explanation
Finds n consecutive equal elements.
Real-World Scenario
Detect repeated characters in a password validator.
Quick Snippet
snippet.cpp
std::search_n(vec.begin(), vec.end(), 2, 5);Full Example
search_n.cpp
// CodeNebula - C++98 Example: search_n
// Compile: g++ -std=c++98 -Wall -Wextra -o example search_n.cpp
// std::search_n searches for N consecutive copies of a given value in a range.
// Returns an iterator to the start of the run, or last if not found.
#include <iostream>
#include <vector>
#include <algorithm>
int main() {
int arr[] = {1, 2, 2, 3, 3, 3, 4, 4, 4, 4};
std::vector<int> v(arr, arr + 10);
std::cout << "Sequence: ";
for (std::vector<int>::iterator it = v.begin(); it != v.end(); ++it) {
std::cout << *it << " ";
}
std::cout << std::endl;
// Find 3 consecutive 3s
std::vector<int>::iterator it = std::search_n(v.begin(), v.end(), 3, 3);
if (it != v.end()) {
std::cout << "Three 3s found at index " << (it - v.begin()) << std::endl;
}
// Find 4 consecutive 4s
it = std::search_n(v.begin(), v.end(), 4, 4);
if (it != v.end()) {
std::cout << "Four 4s found at index " << (it - v.begin()) << std::endl;
}
// Find 2 consecutive 2s
it = std::search_n(v.begin(), v.end(), 2, 2);
if (it != v.end()) {
std::cout << "Two 2s found at index " << (it - v.begin()) << std::endl;
}
// Search for a run that does not exist
it = std::search_n(v.begin(), v.end(), 5, 4);
if (it == v.end()) {
std::cout << "Five 4s not found" << std::endl;
}
return 0;
}
// Expected output:
// Sequence: 1 2 2 3 3 3 4 4 4 4
// Three 3s found at index 3
// Four 4s found at index 6
// Two 2s found at index 1
// Five 4s not found
Run command
g++ -std=c++98 -Wall -Wextra -o example search_n.cpp