C++98stlbeginner
std::accumulate
C++98 · The Foundation · Compiler flag: -std=c++98
Explanation
Folds a range into a single value by applying a binary operation (defaults to addition).
Real-World Scenario
Calculate the total revenue from a list of daily sales in a financial report.
Quick Snippet
snippet.cpp
#include <numeric>
std::vector<int> v = {1, 2, 3, 4};
int sum = std::accumulate(v.begin(), v.end(), 0);Full Example
accumulate.cpp
// CodeNebula - C++98 Example: std::accumulate
// Compile: g++ -std=c++98 -Wall -Wextra -o example accumulate.cpp
#include <iostream>
#include <numeric>
#include <functional>
#include <vector>
#include <string>
std::string concat(const std::string& a, int b) {
char buf[20];
std::sprintf(buf, "%d", b);
return a + (a.empty() ? "" : ", ") + buf;
}
int main() {
int arr[] = {1, 2, 3, 4, 5};
// Simple sum
int sum = std::accumulate(arr, arr + 5, 0);
std::cout << "Sum: " << sum << std::endl;
// Product using multiplies
int product = std::accumulate(arr, arr + 5, 1, std::multiplies<int>());
std::cout << "Product: " << product << std::endl;
// Custom fold: build a comma-separated string
std::vector<int> v(arr, arr + 5);
std::string result = std::accumulate(v.begin(), v.end(),
std::string(""), concat);
std::cout << "Joined: " << result << std::endl;
// Sum of squares using a custom binary operation
// accumulate(init, op) where op(acc, elem) = acc + elem*elem
int sum_sq = 0;
for (int i = 0; i < 5; ++i) sum_sq += arr[i] * arr[i];
std::cout << "Sum of squares: " << sum_sq << std::endl;
return 0;
}
// Expected output:
// Sum: 15
// Product: 120
// Joined: 1, 2, 3, 4, 5
// Sum of squares: 55
Run command
g++ -std=c++98 -Wall -Wextra -o example accumulate.cpp